Ajax call using jquery

function makeAjaxRequest(data1,data2,.....,datax){
    $.ajax({
        'type':'POST',
        async: false,
        url: 'http://www.example.com/some_request_url',
        data:{param1:data1,param2:data2,....,paramx:datax},
        success : function(response) {
            console.log(response); // Using this you can check the posted data in browser console window
            return true;// you can process and return the response as required
            //location.reload(); // or you may reload the current page also
        },
        error: function (jqXHR, exception) {
            // If some error is returned, you can check the details below
            var msg = '';
            if (jqXHR.status === 0) {
                msg = 'Not connect.\n Verify Network.';
            } else if (jqXHR.status == 404) {
                msg = 'Requested page not found. [404]';
            } else if (jqXHR.status == 500) {
                msg = 'Internal Server Error [500].';
            } else if (exception === 'parsererror') {
                msg = 'Requested JSON parse failed.';
            } else if (exception === 'timeout') {
                msg = 'Time out error.';
            } else if (exception === 'abort') {
                msg = 'Ajax request aborted.';
            } else {
                msg = 'Uncaught Error.\n' + jqXHR.responseText;
            }
            $('#post').html(msg); // return the error response in your html page or process it further as required
        }
    });
}